Evolving Card Methods

[Hken]

Evolving Card Methods: Percent of stats you retain.


8
8-14 (tier 1,2,3): 100%
8-6 (tier 2,3): 99.70%
8-2 (tier 3): 97.87%
8-0: 87.13%

7
7-12 (tier 1,2,3): 99.81%
7-6 (tier 2,3): 99.59%
7-2 (tier 3): 97.85%

6
6-10 (tier 1,2,3): 99.63%
6-6 (tier 2,3): 99.48%
6-2 (tier 3): 97.81%

5
5-8 (tier 1,2,3): 98.50%
5-6 (tier 2,3): 98.43%
5-2 (tier 3): 96.85%

4
4-6 (tier 1,2,3): 96.63%
4-4 (tier 2,3): 96.55%
4-2 (tier 3): 95.73%
4-0: 86.63%

*subject to rounding errors
**top method for each number of cards is all possible enhances used
***also assumes max enhance coefficient is 2.5

deduced recommendations:
1. if you are planning on using the card at all, at least enhance at tier 3
2. don't worry about enhancing at tier 1
3. you can get more out of less cards by effectively and efficiently using max enhances
4. if you can, get that 5th card. this enables the usage of 4 max enhances at tier 2 instead of only 2 possible when you only have 4 cards.
5. also try to get that 6th card. this allows your tier 3 to be composed of two ++s. this means they are both 1.4xbase instead of one of them being 1.2xbase (the + in the 5 card method) or 1.0xbase (the basic in the 4 card method).

[randiboy]

How to do 6-6 again? so it's like mime+ enhanced evo with mime enhanced, then mime++ enhanced again to be evoed with another mime++ enhanced?

[kabuchi]

6-6 Mime example, with 6 clean mimes.
Evolve 2 clean Mimes to make 1 Mime+ evolve another 2 Mimes to make 1 Mime+.
So you used 4 of 6 mimes.
Fully enhance the 2 leftover Mime and the 2 Mime+.
Evolve 1 MAX Mime with 1 MAX Mime+. And again.
Now you have 2 Mime ++. Fully enhance the 2 Mime++, then evolve.
* = Max
. . . . . . . . . . . . . [] Mime
. . . . . . . . . . . . // . . . . . \\
. . . . . . *Mime++ . . . . . .*Mime ++
. . . . . // . . . . . \\ . . . . . . // . . . . \\
. . *Mime+ . . *Mime . . *Mime . .*Mime+
. . // . . \\ . . . . . . . . . . . . . . . . . // . . \\
Mime . . Mime . . . . . . . . . . . . . Mime . Mime

6-6, start with 6 cards, max the 6 with * then of course max the final form [].